Aralonia: I feel kind of dirty saying "he has a good point" when I'm referenced in his damn post, but the numbers he comes up with serve a good point.
He used a saturn V to determine missile size IIRC, and milliarcseconds is indeed QUITE TINY. On the other hand, we don't have the resolvingpower to pick out the emitting region of a quasar at 4 gigaparsecs, so as examples go its not definitive.
Suffice to say, though, that tracking a missile in several tens of thousands of kilometers is possible. Difficult, but not impossible. Phalanx tracks cruise missiles moving Mach .86 and intercepts them at ranges of ~10 km IIRC; compensating for the motion of objects moving 300 times faster at 1,000 times the range doesn't seem like it'd be THAT much harder. Slew speed won't be an issue at that range at any rate; fine turret control will be. The target itself is a lot smaller.
Sponge"
Luke Campbell wrote the following:
"
Let's take a 10 MW ERC pumped FEL at just above the lead K-edge. This particular wavelength is used because lead is pretty much the heaviest non-radioactive element you can get, and at just above the highest core level absorption for a material you can get total external reflection at grazing angles - so no absorption or heating of a lead grazing incidence mirror. We will use a 1 meter diameter mirror. The Pb K-edge x-ray transition radiates at 1.4E-11 m. This gives us a divergence angle of 1.4E-11 radians. At 1 light second, we get a spot size of 5 mm, and an intensity of 5E11 W/m2.
Looking at the NIST table of x-ray attenuation coefficients, and noting that 1.4E-11 m is a 88 keV photon, we find an attenuation coefficient of about 0.5 cm2/g for iron (we'll use this for steel), 0.15 cm2/g for graphite (we'll use this for high tech carbon materials) and 0.18 cm2/g for borosilicate glass (a very rough approximation for ceramics). Since graphite has a density of 1.7 g/cm3, we get a 1/e falloff distance (attenuation length) of 4 cm. Iron, with a density of 7.9 g/cm3, has an attenuation length of 0.25 cm. Glass, density 2.2 g/cm3, has an attenuation length of 2.5 cm.
At 1 light second, therefore, the beam is depositing 2E12 W/cm3 in iron at the surface and 7E11 W/cm3 at 0.25 cm depth; 1.2E11 W/cm3 in graphite at the surface and 5E10 W/cm3 at 4 cm depth; and 2E11 W/cm3 in glass at the surface and 7E10 W/cm3 at 2.5 cm depth. Using 6E4 J/cm3 to vaporize iron initially at 300 K, we find that iron flashes to vapor within a microsecond to a depth of 0.9 cm. The glass, assumed to take 4.5E4 J/cm3 to vaporize (roughly appropriate for quartz) will flash to vapor within a microsecond to a depth of 4 cm within a microsecond (sic). Graphite, at 1E5 J/cm3 for vaporization, will flash to vapor to a depth of 0.7 cm within a microsecond (the laser performs better if we let it dwell on graphite for a bit longer, we get a vaporization depth of 10 cm after ten microseconds).
Net conclusion - ravening death beam at one light second."
Sure, 10 MJ isn't a lot of force, but you put it on a pinhead and shit will get busted up it seems. If you take a thin enough section of a warship and exert on it modest forces, grievous damage will still be inflicted. I'd like to say this is my math, but it really isn't. Which... got me thinking.
Mr. Campbell's website got linked. Needless to say, the man's
pretty meticulous.
I ran the 10 MW 5 mm spot through that calculator there and the drilling speed of 30.4 m/sec through structural steel sounds like it'd support the cloven starship idea I was postulating, but converting units says that's a small fraction of a centimeter in a microsecond. Hunh. The battleship Iowa had armor half a meter thick on its turrets; I'm not sure how that'd compare to the pusher plate of an orion drive ship but if that damage calculator is right, a 5 mm spot 10 MW beam would drill through that in, well, 17 milliseconds. Assuming 100 km/sec, in that time your ship would coast 1.7 km plus whatever maneuvers it could perform in 17 milliseconds. Assuming maneuver power of 10 Gs transversally, or 100 m/sec^2, let's see just how much a ship could dodge. r=vt+1/2at^2; at time of initial laser impact assume the targeting computer's deduced the ship's recent velocity and is slewing to track thus vtransverse = 0, a = 100 m/sec^2, t=0.017 seconds. Total distance maneuvered = 1.455 centimeters. Where'd you get your 50 cm radius figure?
So... in the time it takes a 10 MW laser
-according to an online calculator that shows copious math I personally couldn't recite but looks good to me-, a ship could move transversally 3 widths of the 5mm spot. So... if the Death Star can focus on a target at all, -and- that calculator is right... fans are shitty and the death star is indeed a star of death. You don't need to blow a hole in a chunk of steel to cut all the cabling beneath it; you just need to make a gap. If that's true, I don't think you can say that you need the global power output in laser format to ruin somebody's day.
I've run the calculator for an 8 TW laser and a spot size of 5 mm. Drills steel at 2780km/sec. We've moved past "devastating" when we're talking terawatt range beams. Make the spot a little bigger and you can start carving up minor planets. Not vaporizing large areas of them out right, but definately carving 'em up.
Heat is why the weapon in the story was defensive. You don't really want to make a massive radiator and coolant spraying apparatus acceleration-safe... but towing 433 Eros into Earth orbit and using the entire mass as a heatsink, I think a few shots could be managed even at low efficiencies. Mobile superlasers like that would require LARGE ships. Star destroyers, essentially. That kind of engineering is definately a century away, and by then.... well, Sponge, who knows what military quantum leap is over the horizon XD?
EDIT: Oops. Coupla other quickies.
Just as the european X-ray FEL is not a viable antistarship weapon, modern ICBMs aren't either. The warheads themselves are, but the delivery vehicles suck for space engagements, just like experimental FELs suck for toasting martians. Apples and oranges.
Smaller surface area being struck, or being struck face on as opposed to along the sides, means a shorter gash, means less structural damage and less shit getting cut. Also makes you a smaller target and magnifies the effect of maneuvering. Ultimately the orion pusher plate is the end of the ship you want heading into battle.